Question

14. The perimeter of a triangle is 8 + 13a + 7a2 and two of its sides are 2a2 + 3a + 2 and 3a2 -4a -1.
Find the third side of the triangle ​

Answer 1

Step-by-step explanation:

Perimeter = side + side + side

7a² + 13a + 8 = 2a² + 3a + 2 + 3a² - 4a - 1 + side

7a² + 13a + 8 = 5a² - a + 1 + side

side = 2a² + 14a + 7

#answerwithquality #BAL

Answer 2

Answer:

2a^2+14s+7

Step-by-step explanation:

Let the other side is 'x'

Perimeter of triangle = Side+Side+Side

7a^2+13a+8 = 2a^2+3a+3a^2-4a-1+1+x

7a^2+13a+8 = 5a^2-a+1+x

7a^2+13a+8-5a^2-a+1 = x

2a^2+14a+7 = x

Therefore side (x) is equal to 2a^2 + 14 + 7