14. The period of revolution of a planet A around the sun 8 times that of B. how many times is the distance of A from the sun greater than the distance of B from the Sun?
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3
Given,
T
A
=8T
B
According to Kepler's third law,
(
T
B
T
A
)
2
=(
R
B
R
A
)
3
R
B
R
A
=(
T
B
T
A
)
3
2
R
B
R
A
=(
T
B
8T
B
)
3
2
R
B
R
A
=2
3×
3
2
=2
2
=4
R
A
=4R
B
So the correct answer is 4.
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