Question

14. The position co-ordinates of a projectile thrown from
ground are given by y = (12t - 5t2)m and
x = 5t(m). The initial speed of throw is (Here t is in
second)
(1) 10 m/s
(2) 13 m/s
(3) 11 m/s
(4) 17 m/s​

Answer 1

Answer:

dy/dt=12-10t

dx/dt=5

initial mean t=0 time

then dy/dt=12