Math, asked by vimalakrishnan2424, 3 months ago

14. The present ages of A and B are in the ratio 5: 6. Three years ago, their ages were
in the ratio 4:5. Find their present ages.​

Answers

Answered by rdxishwar
0

Step-by-step explanation:

Ratio of the present ages of A and B=5:6

Let age of A=5x

and age of B =6x

3 years hence,

Age of A was =5x−3

and age of B was =6x−3

6x−3

5x−3

=

5

4

⇒25x−15=24x−12

⇒25x−24x=−12+15

⇒x=3

Present ages of A =5x=5×3=15 years

and age of B=6x=6×3=18 years

Answered by netragoyal7
0

Answer:

A = 15

B = 18

hope it helps!

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Step-by-step explanation:

we solve it using the following formulae:

(5x-3)/(6x-3) = 4/5

and we use cross multiplication to solve it further.

this makes it:

5(5x-3) = 4(6x-3)

now, we simplify it further:

25x-15 = 24x-12

now, we transpose the quantities to the respective sides.

25x-24x = -12 + 15

now, we again, simplify it further:

1x = 3.

now, to find the respective ages, we multiply 5 and 6 by 3 to get their ages respectively.

age of:

A = 15

B = 18

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