14. The price of 4 tables and 3 chairs is 16,500. The
price of 2 tables, 2 watches and 2 chairs is 12,000.
Price of 3 tables and 1 chair is :
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Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)Now subtracting (4) from (3) we get,
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)Now subtracting (4) from (3) we get,-7y=-1050
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)Now subtracting (4) from (3) we get,-7y=-1050or, y=150
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)Now subtracting (4) from (3) we get,-7y=-1050or, y=150Then, x=(1950-4×150)/3=(1950-600)/3=1350/3=450
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)Now subtracting (4) from (3) we get,-7y=-1050or, y=150Then, x=(1950-4×150)/3=(1950-600)/3=1350/3=450∴, The total cost of 2 chairs and 1 table is:
Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.Then, by the given question,4x+3y=2250------------(1)3x+4y=1950------------(2)Multiplying (1) with 3 and (2) with 4 we get,12x+9y=6750-----------(3)12x+16y=7800----------(4)Now subtracting (4) from (3) we get,-7y=-1050or, y=150Then, x=(1950-4×150)/3=(1950-600)/3=1350/3=450∴, The total cost of 2 chairs and 1 table is:2y+x=2×150+450=300+450=750
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