Question

14. The ratio of the lengths of two rods is 4:3
The ratio of their coefficients of cubica
expansion is 2:3. Then the ratio of their linea
expansions when they are heated through
same temperature difference is
1) 2:1 2) 1:2 3) 8:9 4) 9:8
plz guys give ans with clarity explanation​

Answer 1

Answer:

4) 8:9

Explanation:

The relation between cubical expansion coefficient and linear expansion coefficient is,

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3α

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1 =

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1 = γ

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1 = γ 2

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1 = γ 2

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1 = γ 2

The relation between cubical expansion coefficient and linear expansion coefficient is,γ=3αThus,α 2 α 1 = γ 2 γ

1

=

= 3

= 32

= 32

= 32

= 32 The linear expansion is given as,

= 32 The linear expansion is given as,Δl=αlΔT

= 32 The linear expansion is given as,Δl=αlΔTTherefore,

= 32 The linear expansion is given as,Δl=αlΔTTherefore,Δl

= 32 The linear expansion is given as,Δl=αlΔTTherefore,Δl 2

= 32 The linear expansion is given as,Δl=αlΔTTherefore,Δl 2Δl

1

1 =(

1 =( α

1 =( α 2

1 =( α 2 α

1 =( α 2 α 1

1 =( α 2 α 1

1 =( α 2 α 1 )×

1 =( α 2 α 1 )× l

1 =( α 2 α 1 )× l 2

1 =( α 2 α 1 )× l 2l

1 =( α 2 α 1 )× l 2l 1

=

= 3

= 32

= 32 ×

= 32 × 3

= 32 × 34

= 32 × 34 =

= 32 × 34 = 9

= 32 × 34 = 98

= 32 × 34 = 98 Hope you understand

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Answer 2

${\fbox{\boxed {\huge{\rm{\red{Answer!!}}}}}}$

The relation between cubical expansion coefficient and linear expansion coefficient is,

${\rm{\gamma = 3 \alpha}}$

Thus,

${\rm{\frac{ \alpha1}{ \alpha 2} = \frac{ \gamma 1}{ \gamma 2} = \frac{2}{3}}}$

The linear expansion is given as,

$\Delta \: l = \alpha \l \Delta\T$

$\implies{\therefore \frac{\Delta l2}{\Delta l1} = \frac{ \alpha 1}{ \alpha 2} × \frac{l1}{l2}}$

${\implies{ \frac{2}{3}\times \frac{4}{3} = \frac{8}{9} }}$

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