14. The sum of n terms of an A.S. is 36. Its first
and last terms, are 1 and 11 respectively. Find
the number of terms and the common
difference.
Answers
Answered by
1
Answer:
n=6
d=2
Step-by-step explanation:
a=1
an=11
Sn=36
Sn=n/2(a+an)
36=n/2(1+11)
36=n/2*12
36*2÷12=n
n=6
an=a+(n-1)d
11=1+(6-1)d
11-1=5d
10=5d
d=10/5
d=2
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