Question

14. The sum of n terms of an A.S. is 36. Its first
and last terms, are 1 and 11 respectively. Find
the number of terms and the common
difference.​

Answer 1

Answer:

n=6

d=2

Step-by-step explanation:

a=1

an=11

Sn=36

Sn=n/2(a+an)

36=n/2(1+11)

36=n/2*12

36*2÷12=n

n=6

an=a+(n-1)d

11=1+(6-1)d

11-1=5d

10=5d

d=10/5

d=2

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