14. The sum of the ages of father and son at present is 110. Ten years ago the product of their ages was
1856. What is the age of the father and the son?
OR
3
Solve using factorisation: i) + +
ii) 20x2 + 20 = 41x
4(3x+1) x+2
1
x+2
X+5
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1
14. (i) ather's present age = a
son's present age = b
a + b = 110
a = 110 - b .........(1)
10 years back
(a - 10) (b - 10) = 1856
(110 - b - 10) (b-10) = 1856
(100 - b) (b - 10) = 1856
100b - b² - 1000 + 10b = 1856
b² - 110b + 2856 = 0
b² - 48b - 62b + 2856 = 0
b(b - 48) - 62(b - 48) = 0
(b - 62) (b - 48) = 0
Their ages = 62, 48
(ii) (The q is not clear)
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