Question

14. The sum of two numbers is 1212 and their
H.C.F. is 101 ; find the numbers.
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Answer 1

Answer:

505, 707

Step-by-step explanation:

let x and y be two numbers;

x + y = 1212

101 x 1 = 101

101 x 2 = 202

101 x 3 = 303

101 x 4 = 404

101 x 5 = 505

101 x 6 = 606

101 x 7 = 707

101 x 8 = 808

101 x 9 = 909

101 x 10 = 1010

so if we observe from 101 table sum of 707 and 505 would be 1212 and their HCF would be 101

Hope you like the way this sum is solved