Question

14. The sum of two numbers is 36 and their HCF is 4. How many pairs of such number are possible? (A) 1 (B)2 (C)3 h (D) 4​

Answer 1

Answer:

3

Step-by-step explanation:

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Answer 2

Answer:

Given Here , HCF of two numbers = 4.

Hence, the numbers can be given by 4p and 4q , where p and q are co-prime. Then,

4p + 4q = 36 ⇒ 4 (p + q) = 36

⇒ p + q = 9

Possible pairs satisfying this condition are : (1 , 8), (4 , 5), (2 , 7)

Hence , number of possible pairs is 3.

Step-by-step explanation:

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