Question

14. The unknown mass of AgNO3 reacts with 4.74 mg of nacl
to given 13.4 gm Agcl and 7.40 gm
NaNO3 . Find the mass of NAgNO3 according
to law of conservation
of mass.
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Answer 1

Answer:

According to law of conservation of mass, total mass in reactant is equal to the total mass in product.So agno3+nacl-> agcl +nano3 .So let mass of agno3 be x .So x+4.74=13.4+7.4=>x=20.8-4.75=16.06 mg.Therefore mass of silver nitrate (agno3) is 16.06 mg