Question

14) The value of a house increases by 10% ever
year. Its present value is 8,80,000.
(1) What will be its value 2 years later?
(ii) What was its value 1 year earlier?​

Answer 1

Step-by-step explanation:

Poplulation ,P=880000

Rate of increase,R=10%

Time,n=2years later & 1 year earlier

1.Value two years later=

P(1+R/100)^n

=880000(1+10/100)^2

=1064800 ans

2.value 1 year earlier=P/(1+R/100)^n

=880000/(1+10/100)^1

=800000ans