Question

(
14. The value of x2 + y2 when x - y = 6 and x + y = 14
is-​

Answer 1

Answer:

(x+y)^2= x^2+y^2+2xy (1)

(x-y)^2=x^2+y^2-2xy (2)

(1)+(2)

6^2+14^2= 232/2=116

hope it will help you

please Mark me brainlist

Answer 2

Step-by-step explanation:

Given is

x–y=6

x= 6+y. -(1)

now,

x+y = 14

put value of x from eqn (1),

(6+y)+y= 14

6+2y= 14

2y = 14–6

2y= 8

y=4

x=6+4

x=10

Now x²+y²= (10)² + (4)²

= 100+16

=116. ans