14. There are 30 children in a class. 12 of them can play badminton; 8 of them can play
table tennis. Find the greatest possible number of children that can play neither of the
two games.
Answers
Answered by
2
Answer:
If we put any of these students into all three group we will reduce all three numbers of every two classes and can never get the total of 32.
Answered by
3
Answer:
given ,
no of children is30
no of children play badminton is 12
no of children play tennis is 8
so no of children neither play 2 games is
30= 12 + 8
30 - 20
10
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