Question

14. Three angles of a quadrilateral are in the ratio 3:5:7. The difference of the least and the
greatest of these angles is 76 . Find all the four angles of the quadrilateral.
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Answer 1

Step-by-step explanation:

let 3 angles be 3x, 5x, 7x

difference given =76

3x-7x=76

-4x=76

x=76/-4

x=-19

- sign is ignored in angles

so x=19

now

3x =3(19)=57

5x=5(19)=95

7x=7(19)= 133

we know sum of angles=360

let z be other angle

57+95+133+z=360

z=360-(57+95+133)

z=360-285

z=75

therefore

57,95,133,75 are angles