Question

14. Two concentric circles have the radii 12 cm and 10.5 cm, respectively. Calculate the area of the space
enclosed by these two circles. (π= 3.14)​

Answer 1

Answer:

3.14[(144+110.25)]

3.14(254.25)

=798.345

Answer 2

area of the space enclosed by these two circles = 105.975 cm ²

Step-by-step explanation:

two concentric circles having radii 12 cm and 10.5 cm

let the radius of outer circle = 12 cm

let the radius of inner circle = 10.5 cm

area of outer circle = $\pi R^2$

R= 12 cm

area of outer circle = $\pi (12)^{2}$= $144\pi$

area of the inner circle =  $\pi r^2$

r= 10.5 cm

area of inner circle = $\pi (10.5)^2$= $110.25\pi$

area of the space enclosed by these two circles= area of outer circle -area of inner circle

= $144\pi$- $110.25\pi$

= $(144- 110.25) \pi$

using $\pi =3.14$

=$33.75\times 3.14$

=105.975 cm²

hence,

area of the space enclosed by these two circles = 105.975 cm ²

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