Math, asked by pkksingh71, 6 months ago

14. Two taps A and B can fill a tank in 12 hours and 15 hours respectively, if each is opened separately. An outlet
tap C can empty the full tank in 10 hours. If all the three taps A, B and C are opened simultaneously find
much of the tank will be filled one hour?

Answers

Answered by Amruthab
0

Step-by-step explanation:

HERE IS YOUR ANSWER :-

TAP A- 12 HOURS x

TAP B- 15 HOURS y

TAP C- 10 HOURS z

Tap A can fill tank in 1 hour = 1/12

Tap B can fill tank in 1 hour = 1/15

Answered by BhumiBakshi
6

Answer:

20 hrs

Step-by-step explanation:

A can fill the tank in =12hrs

A's capacity=1/12

B can fill the tank in= 15hrs

B's capacity=1/15

C can empty the tank in=10hrs

C's capacity=1/10

1/12+1/15-1/10

5+4-6/60

9-6/60

3/60 work

3/60 work can be done in=1hr

1hr's work= 1/1×60/3

= 60/3 or 20Ans

I Hope It Will Help You

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