Question

14. Use congruency of triangles to find the values of x and y in each of the following figures:
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Answer 1

Answer:

a)x=3 y=2    b)x=40° y=30°

Step-by-step explanation:

a) ΔABC ∼ ΔEDC

∴$\frac{AB}{ED}$=$\frac{BC}{DC}$=$\frac{AC}{EC}$

=$\frac{AC}{EC} =1 (AC=EC)$

$By putting AB=x+y ED=5 BC=2x CD=3y\\We get, \frac{x+y}{5} = 1 and \frac{2x}{3y} =1\\=x+y=5 and 2x=3y\\From both equation we get\\x=3 and y=2$

b)InΔABC and ΔADC

AB=AD

BC=DC

AC=AC

by SSS ΔABC≅ΔADC

∴∠BAC=∠DAC

⇒40°=x

also ∠BCA=∠DCA

⇒y=30°

Answer 2

Answer:

this is the answer

Step-by-step explanation:

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