Question

14. Use factor theorem to factorise the following polynomials completely :
(i) x³ + 2x² - 5x - 6​

Answer 1

Answer:

-5x

Step-by-step explanation:

Answer 2

Answer:

$(x + 1)(x + 3)(x - 2)$

Step-by-step explanation:

${x}^{3} + {2x}^{2} - 5x - 6$

${x}^{3} + {x}^{ {}^{2} } + {x}^{2} - 5x - 6$

${x}^{2} (x + 1) + {x}^{2} + x - 6x - 6$

${x}^{2} (x + 1) + x(x + 1) - 6(x + 1)$

$(x + 1)( {x}^{2} + x - 6)$

$(x + 1)( {x}^{2} + 3x - 2x - 6)$

$(x + 1){x(x + 3) - 2(x + 3)}$

$(x + 1)(x + 3)(x - 2)$

Hope it helps you