Question

14. Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the are a of ∆ ABC.
(iii) the length of BD,correct to one decimal place.​

Answer 1

Answer:

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Step-by-step explanation:

i) By pythagoras theorem

AB^2+BC^2=AC^2

(24)^2=(7)^2=AC^2

576+49=AC^2

625=AC^2

AC=√625

AC=25cm

ii) area of right angled triangle = pendicular*base/2

= 7*24/2 = 168/2 = 84cm square

Answer 2

As we know that the triangle given is a right angle triangle
1). So if we apply PGT
Then AB^2 + BC^2 = AC^2
7^2 + 24^2 = AC^2
49 + 576 = AC^2
625 = AC^2
So AC = 25 cm
2). Area of triangle= 1 / 2 * l * b
1/ 2 * 24 * 7
12 * 7
84 cm^2
3). 1/2 * 24 * 7 = 1/2 * 25 * BD
24 * 7 = 25 * BD
BD = 24 * 7 / 25
BD = 6.72cm