14. What is molality? Calculate the mass of sodium carbonate (Na2CO:) required making 500 ml of 0.25M aqueous solution. [Moiar mass of Na2CO3 = 106).
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Molality is the number of moles of solute dissolved in 1 kg of solvent. Molality= mass of solvent in kg number of moles of solute Let W g of sodium carbonate are dissolved.The molar mass of Na2CO3=2(23)+12+3(16)=46+12+48=106 g/molThe number of moles of Na2CO3=106 g/mol W g= 0.009434 W molMass of water = 250 g= 0.250 kg 0.1 m= 0.250 kg 0.009434 W molW= 2.65 gHence, 2.65 grams of Na2CO3 should be dissolved in 250 grams of water to prepare 0.1 m solution
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