14. What is the greatest number of 4 digits which
is
exactly divisible by 40, 48 and 60
Answers
Answer:
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Step-by-step explanation:
Finding the LCM of the numbers 40, 48, and 60. To do this, do a prime factorization of the three numbers
40 = 2×2×2×5
48=2×2×2×2×3
60 =2×2×3×5
All three can be factored using 2, 3, and 5. First take 2. Look for the most times the number 2 is multiplied by itself, which is 2×2×2×2
The 3 is used just once and so it the 5, therefore the LCM is 2×2×2×2×3×5=240
Divide 240 into 9,999, the largest who four-digit number to find that the result is 41 with a remainder of 160. Therefore the largest four-digit number that can be divided by 40, 48, and 60 evenly is
240 ×41=9840
4×15=60 is the greatest number divisible by 4