Question

14. What is the value of m, if one root
of the quadratic equation mx^2 - 7x +
12 = O is 3
- 1
3
ОО​

Answer 1

Answer:

m=1

Step-by-step explanation:

Let, p(x) = mx^2 - 7x + 12

now, p(3) =0 because it is root of the quadratic equation

p(3) = 0 --> (1)

p(3) = m(3) ^2 - 7(3) +12 -> (2)

From (1) & (2),

m(3)^2 - 7(3) + 12 = 0

9m - 21 + 12 = 0

9m - 9 = 0

9m = 9

m = 9/9

m = 1