Question

14.When a force of 770 N acts on a circular disc of radius 7 cm, it produces pressure of Required to answer. Single choice.

a. 0.5 KPa

b. 5 KPa

c. 50 KPa

d. 500 KPa

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Answer 1

c is the correct answer

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Answer 2

Answer:

The answer is option (c) 50KPa

Explanation:

As we know the pressure is defined as the  force applied perpendicular to the surface of an object per unit area over which that force is distributed

Therefore, $Pressure =\frac{Force}{Area}$   → equation 1

In this question, it is given that

The force applied,  $F =770N = 770kgms^{-2}$

And the  radius of a circular disc, $r=7cm=\frac{7}{100} =0.07m$

Hence the area of the circular disc is, A = π$r^{2}$ = $3.14 * (0.07)^2 =0.0154m^{2}$

Therefore, by substituting the values in the above equation 1

  $Pressure =\frac{770}{0.0154} = 50,000kgm^{-1}s^{-2}$ $=50,000Pa$ $=\frac{50,000}{1000} =50KPa$

The required pressure is P = 50KPa