14. Without actual calculating the cubes, find the value of each of the following
1.(-10cube)+(7cube)+(3cube)
2.(28cube)+-15cube+(-13cube)
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We know that if a+b+c=0
Then a^3+b^3+c^3=3abc
1-)-10+7+3=0
(-10)^3+(7)^3+(3)^3=3*-10*7*3
= -630
2-)28+(-15)+(-13)=0
28^3+(-15)^3+(-13)^3=3*28*-15*-13
=16380
Hope it helps you! :-)
Then a^3+b^3+c^3=3abc
1-)-10+7+3=0
(-10)^3+(7)^3+(3)^3=3*-10*7*3
= -630
2-)28+(-15)+(-13)=0
28^3+(-15)^3+(-13)^3=3*28*-15*-13
=16380
Hope it helps you! :-)
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