14. Write the equation for the reaction of zine with hydrochloric acid and balance
the equation. Find out the number of molecules of hydrogen gas produced in
this reaction, when 1 mole of HCl completely reacts at S.T.P.
[Gram molar volume is 22.4 liters at S.T.P.,
Avogadro's number is 6.023 x 1023]
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Answer:
2HCl+Zn -----> ZnCl2 +H2
i mole of HCl completely reacts ... in equation we observe that 1 mole of Zn + 2moles of HCl ------>> 1mole of ZnCl2 + 1mole of H2 molecule 2moles-----> 1 mole of H2 1mole of HCl----> x moles of H2 X=1X1/2=O.5 moles of H2 molecule
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