Question

14. (x^2+ y^2) (p^2+q^2) = 1.​

Answer 1

Step-by-step explanation:

(x^2+ y^2) (p^2+q^2) = 1.

x^2p^2+x^2q^2+y^2p^2+y^2q^2=1

x^2p^2+x^2q^2+y^2p^2+y^2q^2-1=0