Question

14 years ago the age of the mother was 4 times the age of her daughter.the present age of the mother is 2 times the age of her daughter will be 4 years hence. What are their present ages​

Answer 1

Answer:

• The present age of daughter = 25 years
• The present age of her mother = 58 years

Step-by-step explanation:

Given,

• 14 years ago, the age of the mother was 4 times the age of her daughter.
• The present age of the mother is 2 times the age of her daughter will be 4 years hence.

To find,

• Their present ages

Solution,

 Let the present age of daughter be "x years"

and the present age of her mother be "y years"

14 years ago,

mother's age = (y - 14) years

daughter's age = (x - 14) years

As given,

 y - 14 = 4(x - 14)

y - 14 = 4x - 56

4x - y = 56 - 14

4x - y = 42

 y = 4x - 42

4 years later, daughter's age will be = (x + 4) years

As given,

 y = 2(x + 4)

y = 2x + 8

4x - 42 = 2x + 8

4x - 2x = 42 + 8

 2x = 50

   x = 50/2

   x = 25

Substitute value of x in y = 4x - 42

y = 4(25) - 42

y = 100 - 42

y = 58

Therefore,

• The present age of daughter = 25 years
• The present age of her mother = 58 years