14. Zn2+ → Zn(s); E° =-0.76 V
Cu2+ Cu(s); E° = +0.34 V
Which of the following is spontaneous?
1) Zn2+ + Cu-→ Zn + Cu2+
2) Cu2+ + Zn → Cu + Zn2+
3) Zn2+ + Cu2+ + Zn + Cu
4) Zn +Cu Zn2+ + Cu2+
Answers
Answered by
1
Answer:
b)Cu2+ +Zn=Cu+Zn2+
Explanation:
ie,Cu2+ + 2e=Cu
Zn=Zn2 +2e
Cu2+ +Zn=Cu+Zn2+
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