140 g nitrogen react with hydrogen how much gram ammonia get
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The balance reaction of formation of NH3 is as follows:
N2+ 3H2 = 2NH3
Mole of N2= 140 g /28 g/ mole
= 5 mole
Now calculate the number of mole of NH3;
5 Mole N2 *2 Mole NH3 /1 Mole N2
= 10 mole NH3
Amount of NH3 = Number of moles * molar mass
= 10 mole *17 g/ mole
= 170 g NH3
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