Question

1400 is divided into 4 parts such that twice the first part, thrice the second part, 4 times the third part and 12 times the last part are all equal. Find the first part ? I want answers in detail
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Answer 1

Answer:

First part is 600

Step-by-step explanation:

If the parts are a, b, c, d then

2a = 3b = 4c = 12d and

a + b + c + d = 1400

4c = 12d, so c = 12/4d hence c = 3d

3b = 12d, so b = 12/3d hence b = 4d

2a = 12d, so a = 12/2d hence a = 6d

Replace the values in equation

a +b+c+d = 1400

6d + 4d + 3d +d = 1400

14d = 1400

d = 1400/14 = 100

therefore first part a = 6d i.e., a = 6x100 = 600