Math, asked by unew234, 10 months ago

140000×0.000000015
Express in standard form

Answers

Answered by Anonymous

1

Answer:

140000×15/1000000

= 0.0021

Previous Question

Next Question

Similar questions

Math, 5 months ago

57. एक व्यापारी 950 रु0 अंकित मूल्य वाला एक पुरान) कूलर खरीदता है तथा इस पर 10% का एक बट्टा प्राप्त करता रता है. वह इसकी मरम्मत पर 45 रु0 व्यय करता है, यदि वह कूलर को 25% के लाभ पर बेचे, तो कूलर का विक्रय मूल्याहोमा 27 (a) 1020 रु० (bh1925 रु0 (c) 1245 रु० Na)1485 रु0 त्तनात में तीन 12...

English, 5 months ago

. Choose the option that best captures the central idea of the passage from the given quotes. Robotic teachers Vs human teachers robot teachers Will robot teachers better than replace no teacher teachers? Why should robots Replace teachers? (b)...

English, 5 months ago

the list of blinds Akbar got angry when birbal gave him the list. why...

English, 10 months ago

I suggest that he — there. a)goes b)went c)go d)gone.

English, 10 months ago

(3) what the poet wishes for. Ans.

Physics, 1 year ago

Select One Option Correct from the following : A ball hits the floor and rebounds after an inelastic collision. In this case, (A)the momentum of the ball just after the collision is the same as that just before the collision.

Physics, 1 year ago

Select One Correct Option from the following:Two solid cylinders P and Q of same mass and same radius startrolling down a fixed inclined plane from the same height at the same time.Cylinder P has most of its mass concentrated near its surface, while Q hasmost of its mass concentrated near the axis. Whichstatement(s) is (are)correct? (A) Both cylinders P and Q reach the ground at the same time.

Physics, 1 year ago

Select One Correct Option from the following:Using the expression $2d \sin \theta = \lambda$ one calculates the value of d by measuring the corresponding angles $\theta$ in the range $0 to 90^{\circ}$ The wavelength $\lambda$ is exactly known and the error in $\theta$ is constant for all values of $\theta$ . As $\theta$ increases from...