141. A body of mass m is thrown upwards at an angle
with the horizontal with velocity v. While rising in
the velocity of mass after t seconds will be
(a) (v cos 0)2 + (v sin 0)2
(b) (v cos 0 - v sin 0)2 - gt
(c) V02 + g2t2 - (2v sin 6)gt
(d) v2 + g2t2 - (2v cos 6)gt
Answers
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1
Answer:
c
Explanation:
vo2+g2t2-(2vsino) gt
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