Question

142. A walks 10 metres towards East and then 10 metres to his right. Then every time turning
to his left, he walks 5, 15 and 15 metres respectively. How far is he now from his starting
point (in meters)?​

Answer 1

The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T)

Since TS = OP + QR, so T lies in line with O. A’s distance from the starting point O = OT = (RS – PQ) = (15 – 10)m = 5 m.

Answer 2

Answer is 5 m because 1 to 6 is equal to 4.5 to 5