Question

144 L of liquid P and 216 L of liquid Q are to be packed in containers of the same size. The minimum no of containers required ????

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Answer 1

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The minimum number of containers required are 72.

Step-by-step explanation:

Given:

144L of liquid P and 216L of liquid Q are to be packed in container of the same size.

To find:

the minimum number of containers required

Solution:

The total sum of liquids = 144 + 216 = 360

HCF of 144 and 216 = 360

The number of containers required = 5 360 = 72

Result:

The minimum number of containers required are 72.

Answer 2

Answer:

72

Step-by-step explanation:

The minimum number of containers required are 72.

Step-by-step explanation:

Given:

144L of liquid P and 216L of liquid Q are to be packed in container of the same size.

To find:

the minimum number of containers required

Solution:

The total sum of liquids = 144 + 216 = 360

HCF of 144 and 216 = 360

The number of containers required = 5 360 = 72

Result:

The minimum number of containers required are 72.