Math, asked by sarthaktrivedi26, 1 month ago

144 l of liquid P and 216 l of liquid Q are to be packed in the containers of the same size. The maximum number of containers required are​

Answers

Answered by abhisheksuresh208
0

Answer:

It required 5 containers.

Step-by-step explanation:

Since we have given that  

Quantity of liquid P = 144 L

Quantity of liquid Q = 216 L

So, We need to find the minimum number of containers.

So, We will find L.C.M. of 144 and 216.

lcm of 144 and 216 = 432.

So, it will require 432 L of container.

So, Number of container for liquid P would be

Number of container for liquid Q would be

Hence, it required 3+2 =5 containers.

Answered by aaa722
0

Answer:

144 l of liquid P and 216 l of liquid Q are to be packed in the containers of the same size. The maximum number of containers required are

Step-by-step explanation:

144 l of liquid P and 216 l of liquid Q are to be packed in the containers of the same size. The maximum number of containers required are

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