144L of liquid P and 216 L of liquid Q are to be packed in containers of the same size. The minimum number of containers required are
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The minimum number of containers required are 5.
- There is 144 L of liquid P and 216 L of Liquid Q are to be packed in containers of the same size.
- We have to find the minimum numbers of containers required to store both the liquids.
- We have to find the HCF of both the amounts to compute the maximum amount which a single container must sustain within it.
- Therefore, HCF of 144 and 216 :
144 = 2×2×2×2×3×3
216 = 2×2×2×3×3×3
Therefore HCF = 2×2×2×3×3 = 72.
- Now minimum number of containers of liquid P will be 144 / 72 = 2.
- Minimum number of containers of liquid P will be 216 / 72 = 3.
- Therefore, minimum number of containers required to fill both the liquids = 3 + 2 = 5
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