Question

144L of liquid P and 216 L of liquid Q are to be packed in containers of the same size. The minimum number of containers required are

Answer 1

Answer:

see this attachment...i hope it's help to you

Answer 2

The minimum number of containers required are 5.

• There is 144 L of liquid P and 216 L of Liquid Q are to be packed in containers of the same size.

• We have to find the minimum numbers of containers required to store both the liquids.

• We have to find the HCF of both the amounts to compute the maximum amount which a single container must sustain within it.

• Therefore, HCF of 144 and 216 :

144 = 2×2×2×2×3×3

216 = 2×2×2×3×3×3

Therefore HCF = 2×2×2×3×3 = 72.

• Now minimum number of containers of liquid P will be 144 / 72 = 2.

• Minimum number of containers of liquid P will be 216 / 72 = 3.

• Therefore, minimum number of containers required to fill both the liquids = 3 + 2 = 5