Question

1450 ml N from a porous closed container, it takes 48 minutes for air to escape. So in 60 minutes CH4, how much volume of CH4 will be escape?​

Answer 1

1360 mL of CH4 will escape from the container in 60 minutes.

To find,

In 60 minutes of CH4, the amount of volume of CH4 will escape.

Given,

1450 ml N from a porous closed container, it takes 48 minutes for the air to escape.

Solution,

Assuming that the conditions of the container remain constant during the experiment, we can use Graham's law of effusion to calculate the volume of methane (CH4) that will escape from the container in 60 minutes.

According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically,

Rate of effusion ∝ 1/√(molar mass)

Since nitrogen (N2) and methane (CH4) are both gases at the same temperature and pressure, we can use the following ratio:

Rate of effusion of N2 / Rate of effusion of CH4 = √(molar mass of CH4 / molar mass of N2)

The molar mass of nitrogen is 28 g/mol, and the molar mass of methane is 16 g/mol. Therefore,

Rate of effusion of N2 / Rate of effusion of CH4 = √(16/28) = 0.75

This means that the rate of effusion of methane is 0.75 times the rate of effusion of nitrogen under the same conditions.

We know that 1450 mL of nitrogen escaped from the container in 48 minutes. Therefore, the rate of effusion of nitrogen is:

Rate of effusion of N2 = 1450 mL / 48 min = 30.21 mL/min

Using the ratio above, we can calculate the rate of effusion of methane:

Rate of effusion of CH4 = 0.75 x 30.21 mL/min = 22.66 mL/min

Therefore, in 60 minutes, the volume of methane that will escape from the container is:

Volume of CH4 = Rate of effusion of CH4 x Time = 22.66 mL/min x 60 min = 1360 mL

So 1360 mL of CH4 will escape from the container in 60 minutes.

For further reference visit,

https://brainly.in/question/6895943?referrer=searchResults

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