147- One digit is right but in its wrong place. 189- One digit is right and in its place
964- Two digits are correct but both are in wrong place.
523- All digits are wrong
286- One digit is right but in ts wrong place
Answers
Answer:
acc to the condition the are 769/679
Answer:
Concept:
Crack the code puzzle
Step-by-step explanation:
given:
147 - One digit is right but in the wrong place
189 - One digit is right and in its place
964 - Two digits are correct but both are in the wrong place
523 - All digits are wrong
286 - One digit is right but in the wrong place
Find:
What are the 3 numbers?
Solution:
Statement (a): 147 - One digit is correct, however, it is incorrectly placed.
189 (a) - One digit is correct and in its proper place
Statement (c):964 - Two digits are right, but they are in the incorrect order.
All digits are incorrect in the statement (d):523
Statement (e):286 - One digit is correct, however, it is in the incorrect location
We can deduce from (a) and (b) that 1 is not present.
We can deduce from (b) and (e) that 8 is not present.
As a result of (b), we can deduce that The third digit is 9.
As a result of (a), the second digit is 7.
As a result of (e), the first digit is 6.
So the code is 679.
#SPJ3