Math, asked by ajm8, 8 months ago

147- One digit is right but in its wrong place. 189- One digit is right and in its place
964- Two digits are correct but both are in wrong place.
523- All digits are wrong
286- One digit is right but in ts wrong place

Answers

Answered by geethikasri
51

Answer:

acc to the condition the are 769/679

Answered by bharathparasad577
0

Answer:

Concept:

Crack the code puzzle

Step-by-step explanation:

given:

147 - One digit is right but in the wrong place

189 - One digit is right and in its place

964 - Two digits are correct but both are in the wrong place

523 - All digits are wrong

286 - One digit is right but in the wrong place

Find:

What are the 3 numbers?

Solution:

Statement (a): 147 - One digit is correct, however, it is incorrectly placed.

189 (a) - One digit is correct and in its proper place

Statement (c):964 - Two digits are right, but they are in the incorrect order.

All digits are incorrect in the statement (d):523

Statement (e):286 - One digit is correct, however, it is in the incorrect location

We can deduce from (a) and (b) that 1 is not present.

We can deduce from (b) and (e) that 8 is not present.

As a result of (b), we can deduce that The third digit is 9.

As a result of (a), the second digit is 7.

As a result of (e), the first digit is 6.

So the code is 679.

#SPJ3

Similar questions