Question

148/x+231/y=527/x;231/x+148/y=610/xy find the solution

Answer 1

Dear student

I think, the question is having typing error, Corrected question is qiven below

148/x + 231/y =527/xy

231/x +148/y = 610/xy 

Find the values of x and y :
__________________________________________________
Solution :
148/x + 231/y =527/xy

(148y+231x)/xy = 527/xy

231x + 148y = 527 ----------------(1)

231/x +148/y = 610/xy 

(231y+148x)/xy = 610/xy

148x+231y=610 ---------------------(2)

Now multiply equation (1) with 148 and equation (2 )with 231 we get :

34188x+21904y=77996 ------------(3)
34188x+53361y=140910-----------(4)

On solving equation 3 and 4 we get :

34188x+21904y=77996 
34188x+53361y=140910
-             -               -
===================
- 31457y= -62914 
   31457y=62914
y=62914/31457
y=2

On substituting the value of y in equation 1 we get :
231x+124x2 =527

231x=527-296

231x=231
x=1

*************************************
Hence x =1 and y=2
**************************************