Math, asked by Yashikayelmule, 1 year ago

148/x+231/y=527/xy;231/x+148/y=610/xy solve by elimination method

Answers

Answered by saitejassb
3
148y/xy + 231x/xy = 527/xy 

<=> 

148y + 231x = 527 

and 

231y/xy + 148x/xy = 610/xy 

<=> 

231y + 148x = 610 

=> 

148y + 231x = 527 

231y + 148x = 610 

<=> 

34188y + 53361x = 121737 

34188y + 21904x = 90280 

<=> 

31457x = 31457 

<=> 

x = 1 

231y + 148x = 610 

<=> 

231y + 148 = 610 

<=> 

231y = 462 

<=> 

y = 2 


Answer : 

x = 1 

and 

y = 2 

******* 

Verification : 

148/1 + 231/2 = 

148 + 115.5 = 263.5 

527/(1 * 2) = 527/2 = 263.5 ===> OK. 


231/1 + 148/2 = 

231 + 74 = 305 

610/(1 * 2) = 610/2 = 305 ===> OK. 
=2
Hope it helps you

Yashikayelmule: thanks
Yashikayelmule: i want step by step
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