Question

148x+231y=527. 231x+148y=610

Answer 1

148x+231y=527 ---------------- (1)

 

231x+148y=610 ---------------- (2)

 

Multiplying eqn. 1 by 231 and eqn. 2 by 148, we get

 

148x * 231 + 231y * 231 = 527 * 231 --------------- (3)

 

231x * 148 + 148y * 148 = 610 * 148 --------------- (4)

 

Subtracting eqn. 3 from eqn. 4, we get

 

231x * 148 + 148y * 148 = 610 * 148 --------------- (4)

-

148x * 231 + 231y * 231 = 527 * 231 --------------- (3)

 

+21904y = 90280

- 53361y = -121737

 

-31457y = - 31457

 

Or y = - 31457/- 31457 = 1.

 

Substituting the value of y = 1 in eqn. 1, we get

 

148x+231*1=527

 

Or 148x = 527-231 = 296

 

Or x = 296/148 = 2.

 

Thus, x = 2 and y = 1.