Question

148x+231y=527 231x+148y=610 find x and y?

Answer 1

Answer:

y=1 x=2

Step-by-step explanation:

148x+231y=527

231x+148y=627

------------------------

379x+379y=1137

x+y=3

148x+231y=527

-231x-148y=-610

---------------------------

-83x+83y=-83

-x+y=-1

x+y=3

-x+y=-1

-----------

2y=2

y=1

x+y=3

x+1=3

x=2

Answer 2

Value of x= 2 and y= 1.

Given:

• $148x + 231y = 527...eq1$
• and $231x + 148y = 610...eq2$

To find:

• Find the value of x and y.

Solution:

Concept to be used:

• Add both equations.
• Subtract both equations.
• Solve new equations to find x and y.

Step 1:

Add both equations.

$148x + 231y = 527 \\ 231x + 148y = 610 \\ - - - - - - - - - \\37 9x + 379y =11 37 \\ - - - - - - - - -$

or

$\bf x + y = 3...eq3$

Step 2:

Subtract both equations.

$148x + 231y = 527 \\ 231x + 148y = 610 \\ ( - ) \: \: ( - ) \: \: \: ( - ) \\ - - - - - - - - - \\ - 8 3x + 83y = - 83 \\ - - - - - - - - -$

or

$\bf x - y = 1...eq4$

Step 3:

Add both equations 3 and 4.

$x + y = 3 \\ x - y = 1 \\ - - - - - - \\ 2x = 4 \\ - - - - - -$

or

$\bf \red{x = 2 }$

Put the value of x in eq3

$2 + y = 3$

or

$\bf \red{y = 1}$

Thus,

Value of x= 2 and y= 1.

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