Question

149. A ball is thrown vertically downward with a
velocity of 20 m/s from the top of a tower. It hits
the ground after some time with a velocity of
80 m/s. The height of the tower is: (g= 10 m/s2)
300 m
(2)
360 m
(3)
340 m
(4)
320 m
c​

Answer 1

Answer:

Height of the tower is 300 m.

Explanation:

Given :-

Initial velocity (u) = 20 m/s

Final velocity (v) = 80 m/s

Acceleration due to gravity (g) = 10 m/s²

To find :-

Height (h)

Solution :-

Using equation of motion,

v² - u² = 2gh

Substituting the values,

80² - 20² = 2 × 10 × h

6400 - 400 = 20h

6000 = 20h

h = 6000/20

h = 300

∴ Height of the tower is 300 m.

Answer 2

Answer:

300

Explanation:

49. A ball is thrown vertically downward with a

velocity of 20 m/s from the top of a tower. It hits

the ground after some time with a velocity of

80 m/s. The height of the tower is: (g= 10 m/s2)

300 m

(2)

360 m

(3)

340 m

(4)

320 m

c​