Question

149 gm of luck is dissolve in 10 l of an aqueous solution determine the molarity of the solution​

Answer 1

Answer:

2.778

10% w/w means 10 g NaOH dissolves in 100 g solution or 10 g NaOHis present in (100−10=90g) of water.

∴ Weight of NaOH=10g

Mol. wt. of NaOH=23+16+1=40gmol

−1

Moles of NaOH=

40

10

=

4

1

=0.25

Weight of solvent (water) = 90 g

∴ Molality (m) =

Wt.ofwater(ing)

MolesofNaOH×1000

=

90

0.25×1000

=2.778