149. In parallelogram FIST, find SFT, OST and ST0
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Answer:
∠SFT = 45°
∠OST = 75°
∠STO = 35°
Explanation:
In this parallelogram FIST,
FT ║SI
So, with TI as transversal, we can say that,
∠TIS =∠ITF [Alternate Interior Angles]
Similarly,
∠TIF =∠ITS [Alternate Interior Angles]
Now from figure,
∠ITS =∠OTS = ∠STO and ∠ITF = ∠OTF
So, ∠STO = 35°
From figure,
∠FOT = 110°
Then by linear pair concept,
∠FOT + ∠TOS = 180°
=> ∠TOS = 180° - 110° = 70°
Now, in Δ SOT,
∠STO = 35°
∠TOS = 70°
Then, ∠OST = 180° - [35° + 70°] = 75°
In Δ FOT,
∠OTF = 25°
∠FOT = 110°
Then, ∠OFT = 180° - (110° + 25°) = 45°
From figure,
∠OFT = ∠SFT
So,
∠SFT = 45°
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