Question

149.
The most contributing tautomeric enol form of
MeCOCH, CO2Et is :
[JEE (WB) 2012]
(a) HC=C(OH)CH-CO-Et
(b) Me(OH)=CHCO, Et
ogniataron
i grivolto
(c) MeCOCH=C(OH)OEt
(d) H2C=C(OH)CH=C(OH)Et​

Answer 1

Answer:

your answer is option (b)

Me(OH)=CHCO Et