Chemistry, asked by mukulgautam92, 9 months ago

149.
The most contributing tautomeric enol form of
MeCOCH, CO2Et is :
[JEE (WB) 2012]
(a) HC=C(OH)CH-CO-Et
(b) Me(OH)=CHCO, Et
ogniataron
i grivolto
(c) MeCOCH=C(OH)OEt
(d) H2C=C(OH)CH=C(OH)Et

Answers

Answered by qtwwwuqi

0

Answer:

your answer is option (b)

Me(OH)=CHCO Et

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