Question

14a^2b+2b^2d-10abd-35abc factorise​

Answer 1

Answer:

Let us first find the HCF of all the terms of the given polynomial 2a

5

b

3

−14a

2

b

2

+4a

3

b by factoring the terms as follows:

2a

5

b

3

=2×a×a×a×a×a×b×b×b

14a

2

b

2

=2×7×a×a×b×b

4a

3

b=2×2×a×a×a×b

Therefore, HCF=2×a×a×b=2a

2

b

Now, we factor out the HCF from each term of the polynomial 2a

5

b

3

−14a

2

b

2

+4a

3

b as shown below:

2a

5

b

3

−14a

2

b

2

+4a

3

b=2a

2

b(a

3

b

2

−7b+2a)

Hence, 2a

5

b

3

−14a

2

b

2

+4a

3

b=2a

2

b(a

3

b

2

−7b+2a).