14g H2 react with 44.8liter N2 at S.T.P find C.R also find remaining amount gass of H2 reaction
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Answer:
Molar mass of
N
2
→
28
g/mol
So 100 g
N
2
=
100
g
28
g
mol
=
100
28
m
o
l
=
25
7
m
o
l
The equation of the reaction is
N
2
+
3
H
2
→
2
N
H
3
The stochiometry of this equation reveals that 1 mol
N
2
produces 2 moles
N
H
3
having volume
2
×
22.4
L
at STP ( when reacted with excess
H
2
)
So 100g or.
25
7
mol
N
2
produces
25
7
m
o
l
×
2
×
22.4
L
mol
N
H
3
=
160
L
N
H
3
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