14th question for brainiest
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Anonymous:
answer is 40
Because <b+<d=180
<b=180-130
<b=50
<bca=90 angle in a semi circle
<a=180-<b-<bca
<cab=180-140
<cab=40
OH LOL, I didn't see the CAB part. :-P
It is 40.
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Angle D + Angle B = 180 (We know that opposite angles in a cyclic quadrilateral add up to
180)
So angle CBA = 180-130=50°
Angle ACB=90°
Angle B + ACB + CAB =180 (angle sum prop of triangle)
(ie)50+90+ACB=180
ACB=180-140
=40
180)
So angle CBA = 180-130=50°
Angle ACB=90°
Angle B + ACB + CAB =180 (angle sum prop of triangle)
(ie)50+90+ACB=180
ACB=180-140
=40
Is always 90
you again copy my
No dear...i just wrote my ans
ok
i am just joking
...its fine....
Haw....what?...i dont get u dear?
Nyway bye
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